Number theory
Erdős 936 - two pow add one
Is powerful for finitely many ?References
No one has attempted this yet.
Formal statement
Lean type
True ↔ Erdos936.EventuallyNotPowerful fun x => 2 ^ x + 1What you must prove
import FormalConjectures.ErdosProblems.«936»
import TaskSupport
namespace Bounty
theorem target : fcTypeOfName% "Erdos936.erdos_936.variants.two_pow_add_one" := by
sorry
end Bounty
Pinned source: FormalConjectures/ErdosProblems/936.lean
- Source type SHA-256
- sha256:56857fb4f011f4102531040d48634aa7cbdf8195d55c530ad57a8535888868a2
- Task id
- fc-379fc029-variants-two-pow-add-one-4646479eea-formalized-v1
- Task commitment
- sha256:2b04a42deef4628bd7bab127a480edb8fcf130b9d53392d8c28c48ad9f575106
Something wrong with this formalization?
A statement that does not faithfully capture the original conjecture is the one real risk here, so we would rather hear about it early - before someone spends weeks on it.